TGT PGT Physics Free Practice Test: Straight Line Motion [20+ Top MCQs]

TGT PGT Physics Free Practice Test: Straight Line Motion
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Ace your TGT PGT Physics 2025 with our free practice test on Straight Line Motion! Featuring 20+ MCQs in English and Hindi, this test by Physics Scholar is your key to mastering kinematics. Start now and boost your exam prep!

Short Notes on Straight Line Motion for TGT PGT Physics

Revise these key formulas and one-liner points for Straight Line Motion (Kinematics) tailored for TGT/PGT 2025 syllabus before taking the test:

Key Formulas

  1. First Equation of Motion: v = u + at
  2. Second Equation of Motion: s = ut + \frac{1}{2}at^2
  3. Third Equation of Motion: v^2 = u^2 + 2as
  4. Average Velocity: v_{\text{avg}} = \frac{u + v}{2} (for uniform acceleration)
  5. Distance in nth Second: s_n = u + \frac{a}{2}(2n - 1)
  6. Relative Velocity: v_{\text{AB}} = v_A - v_B
  7. Free Fall Acceleration: g = 9.8 , \text{m/s}^2

One-Liner Key Points

  • Uniform Motion: Constant velocity, a = 0.
  • Uniformly Accelerated Motion: Constant acceleration, use equations of motion.
  • Displacement: Vector quantity; shortest path between initial and final positions.
  • Distance: Scalar quantity; total path length.
  • Velocity-Time Graph: Slope gives acceleration; area under curve gives displacement.
  • Relative Velocity: Depends on reference frame; subtract velocities for same-direction motion.
  • Free Fall: Objects under gravity have a = g, u = 0 if dropped.

“Revise these formulas, then test your kinematics skills!”

Take the Free Straight Line Motion Practice Test Now!

Ready to conquer TGT PGT Physics 2025? Our free 20+ MCQ practice test on Straight Line Motion covers the UPSESSB and TGT/PGT syllabi in English and Hindi. Powered by Quiz and Survey Master (QSM), it’s designed for exam success.

Why This Test?

  • Exam-Like Experience: One question per page for focus and time management.
  • Bilingual Support: Questions and solutions in English and Hindi.
  • Detailed Solutions: Download a PDF with step-by-step explanations.
  • Score Tracking: Instant feedback with leaderboard rankings.

“Master Straight Line Motion one MCQ at a time. Start now!”

1. 
If displacement of a particle is zero, the distance covered: यदि कण का विस्थापन शून्य हो, तो तय की गयी दूरी -

2. 
If the distance covered is zero, the displacement: यदि तय की गयी दूरी शून्य हो, तो विस्थापन -

3. 
The numerical value of the ratio of displacement to distance is : विस्थापन तथा दूरी के अनुपात का आंकिक मान है -

4. 
The position x of a particle varies with time t as $ x=a t^{2}-b t^{3} $. The acceleration at time $ t $ of the particle will be equal to zero, where $ t $ is equal to

एक कण की स्थिति x समय t के अनुसार इस प्रकार परिवर्तित होता है, $\mathrm{x}=\mathrm{at}^{2}-\mathrm{bt}^{3}$, समय t पर कण का त्वरण शून्य है, तो $ t $ का मान है

5. 
A body of 5 kg is moving with a velocity 20 m/s. If a force of 100 N is applied on it for 10 sec in the same direction as its velocity. What will now be the velocity of the body? 5 kg का एक पिण्ड 20 m/s के वेग से गतिमान है। यदि इसके वेग की दिशा में 100 N बल 10 से० तक लगाया जाये तो अब इसका पिण्ड का वेग होगा -

6. 
A body at rest is acted upon by a constant force. What is the nature of the displacement time graph? विराम में रखी एक वस्तु पर एक नियत बल लगाया जाता है। तो विस्थापन समय ग्राफ की प्रकृति होगी

7. 
The slope of the velocity-time graph for retorted motion is : मंदित गति मे वेग-समय ग्राफ की प्रवणता होती है

8. 
The area of the acceleration displacement curve of a body gives: किसी पिण्ड के त्वरण- विस्थापन वक का क्षेत्रफल बताता है

9. 
A particle starts its motion from rest under the action of a constant force. If the distance covered in first 10 seconds is $ S_1 $ and that covered in the first 20 seconds is $ S_2 $, then: एक कण नियत बल के प्रभाव में विरामावस्था से गति प्रारम्भ करता है, यदि पहले 10 से०. में तय की गयी दूरी $ S_1 $ तथा पहले 20 से० में तय की गयी दूरी $S_2$ हो, तब -

10. 
In a motion with constant acceleration the velocity is reduced to zero in 5 seconds and after covering a distance of 100 m . The distance covered by the particle in next 5 second will be :

एक समान त्वरित गति में 5 से० में 100 मी० दूरी तय के बाद कण का वेग शून्य हो जाता है। अगले 5 से० में कण द्वारा तय की गयी दूरी है -

11. 
Pick up the correct statement: सही कथन चुनें -

  • (a) Area under a-t graph gives velocity/ a-t ग्राफ का क्षेत्रफल वेग देता है।
  • (b) Area under a- t graph gives change in velocity/ a-t ग्राफ का क्षेत्रफल वेग में परिवर्तन देता है।
  • (c) A body, whatever be its motion, is always at rest in a frame of reference fixed to body itself/ किसी भी प्रकार की गति में कण से निर्देश फेम में कण सदैव विराम में होता है।
  • (d) None of the above/इनमें से कोई नहीं

12. 
The ratio distance traveled by a body falling from rest in fourth and fifth second is : विराम से गिरतह हुई वस्तु द्वारा चौथे तथा 5 वें से० में तय की गयी दूरियों का अनुपात है -

(a) ( 4: 5 )
(b) ( 5: 7 )
(c) ( 7: 9 )
(d) ( 9: 11 )

13. 
If the speed of the particle is increased three times how much times will the stopping distance increases? यदि कण की चाल तीन गुनी कर दी जाय तो अवरोधन दूरी कितने गुना बढ़. जायेगी -

14. 
Which is incorrect statement regarding distance: दूरी के लिये कौन सा कथन असत्य है-

15. 
If x is position and a acceleration then which graph represents the uniform motion: यदि x स्थिति तथा a त्वरण हो, तो कौन सा ग्राफ एकसमान गति को प्रदर्शित करता है -

16. 
The numerical value of the ratio of displacement to distance is : विस्थापन तथा दूरी के अनुपात का आंकिक मान है -

17. 
If the distance covered is zero, the displacement: यदि तय की गयी दूरी शून्य हो, तो विस्थापन -

18. 
A particle moves in a straight line with retardation proportional to its displacement. Its loss of kinetic energy for any displacement x is proportional to : एक कण एक सरलरेखीय पथ पर इस प्रकार चलता है कि मन्दन, विस्थापन के अनुक्रमानुपाती है। x विस्थापन पर गतिज ऊर्जा की हानि अनुक्रमानुपाती होगी -

19. 
The area of the acceleration displacement curve of a body gives: किसी पिण्ड के त्वरण- विस्थापन वक का क्षेत्रफल बताता है-

20. 
A particle has an initial velocity $( 3 \hat{i}+4 \hat{j} )$ and an acceleration of $( 0.4 \hat{i}+0.3 \hat{j} )$. Its speed after 10 s is : एक कण का प्रारम्भिक वेग $( 3 \hat{i}+4 \hat{\mathrm{j}} )$ तथा त्वरण $( 0.4 \hat{i}+0.3 \hat{j} )$ है, 10 से० बाद इसकी चाल होगी -

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Why Straight Line Motion Is Key for TGT PGT Physics

Straight Line Motion is a foundational topic in Mechanics, heavily tested in TGT and PGT Physics exams. Expect questions like:

  • “Find the time to reach maximum height in free fall.”
  • “Use s = ut + \frac{1}{2}at^2 to calculate displacement.”

Our 20+ MCQs cover uniform motion, accelerated motion, relative velocity, and motion graphs, aligned with the 2025 syllabus. Practice to nail these concepts and boost your score!

Key Features of This Practice Test

  • Comprehensive Coverage: Includes equations of motion, free fall, and graph-based problems.
  • Realistic Format: Timed, bilingual MCQs for exam readiness.
  • Free & Expert-Designed: Crafted by physics experts like Anup Sir.
  • Leaderboard: Compare scores with other aspirants.

Why Choose Physics Scholar?

Physics Scholar is your trusted platform for TGT PGT Physics 2025 prep. Join thousands who use our:

  • Free Test Series: From Vector Algebra to Units & Measurements, plus full-length mocks.
  • Previous Year Papers: Solved questions to understand exam trends.
  • Expert Resources: Study guides for Uttar Pradesh and national exams.

How to Ace Your Prep

  1. Review Notes: Study the formulas and points above.
  2. Take the Test: Attempt the 20+ MCQs in a timed setting.
  3. Analyze Performance: Use the bilingual solutions PDF to improve.
  4. Focus on Weaknesses: Revisit topics like motion graphs or relative velocity.

10 FAQs on Straight Line Motion (From Past TGT/PGT Exams)

These frequently asked questions from past TGT/PGT exams will boost your prep and search ranking:

  1. What is the first equation of motion?
    v = u + at, where v is final velocity, u is initial velocity, a is acceleration, and t is time.
  2. How do you calculate displacement in uniformly accelerated motion?
    Use s = ut + \frac{1}{2}at^2.
  3. What is the difference between speed and velocity?
    Speed is scalar (magnitude only); velocity is a vector (magnitude and direction).
  4. What does the slope of a velocity-time graph represent?
    Acceleration.
  5. How is relative velocity calculated?
    v_{\text{AB}} = v_A - v_B for objects moving in the same direction.
  6. What is the third equation of motion?
    v^2 = u^2 + 2as, linking velocity, acceleration, and displacement.
  7. How do you find the distance traveled in the nth second?
    s_n = u + \frac{a}{2}(2n - 1).
  8. What is the acceleration in free fall?
    g = 9.8 , \text{m/s}^2 (downward).
  9. What does the area under a velocity-time graph represent?
    Displacement.
  10. What happens to velocity in uniform motion?
    Remains constant (a = 0).

Kickstart Your TGT PGT Physics Success!

Master Straight Line Motion for TGT PGT Physics 2025 with our free 20+ MCQ test in English and Hindi. With expert solutions and exam-like practice, you’re set to shine. Start now at Physics Scholar!

“Physics moves the world; this test moves you closer to your teaching dream!”

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Amit Patel
Amit Patel

Hello!  I am Amit Patel From Uttar Pradesh. I have done my  Masters in Physics (2018) & B.Ed. (Education), Now I am working with Physics Scholar (By Anup Sir) as a Technical Team Member & content writer specially on Educational Carrier Counselling for Teaching Exams. I am a lover of Physics so i also explore to write articles on Science & Technology.

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