[100% Free] TGT PGT Physics Practice Test On Projectile Motion With Short Notes

Crack TGT PGT Physics 2025 with Physics Scholar’s free projectile motion practice test and easy-to-revise notes. Learn key formulas and concepts to boost your score!

[100% Free] TGT PGT Physics Practice Test On Projectile Motion With Short Notes
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Getting ready for the TGT PGT Physics 2025 exams? Projectile motion is one of those topics that can make or break your score. It’s not just about memorising formulas—it’s about understanding the concepts and solving problems confidently.

At Physics Scholar, we’ve put together simple, to-the-point revision notes to help you brush up on projectile motion, plus a free practice test to check how well you’re prepared. Whether you’re aiming to become a Trained Graduate Teacher (TGT) or Post Graduate Teacher (PGT), this guide is here to help you nail this topic.

Quick Revision Notes on Projectile Motion

Projectile motion is all about objects—like a ball or a stone—thrown into the air, moving under gravity’s pull. It’s a big deal in TGT PGT Physics exams, so let’s break it down into bite-sized pieces for quick revision.

What You Need to Know

  • What is it? When you throw something, it follows a curved path because of gravity. That’s projectile motion.
  • Two Types:
    • Horizontal Projection: Think of pushing a book off a table—it falls straight down but moves forward too.
    • Angular Projection: Like kicking a football at an angle—it goes up, then down, in a curve.
  • Key Points:
    • Gravity only affects the vertical motion (g = 9.8 , \text{m/s}^2).
    • Horizontal motion? No forces (if we ignore air), so it’s steady.
    • The path (or trajectory) is always a parabola.
  • Important Terms:
    • Range: How far it travels horizontally.
    • Time of Flight: How long it’s in the air.
    • Maximum Height: The highest point it reaches.

Must-Know Formulas

Let’s get to the formulas you’ll need for angular projection (when you throw something with speed u at an angle \theta):

  1. Breaking Down the Speed:
    • Horizontal speed: u_x = u \cos \theta
    • Vertical speed: u_y = u \sin \theta
  2. Time of Flight (how long it’s in the air):
    • T = \frac{2u \sin \theta}{g}
  3. Maximum Height (how high it goes):
    • H = \frac{u^2 \sin^2 \theta}{2g}
  4. Range (how far it lands):
    • R = \frac{u^2 \sin 2\theta}{g}
    • Pro tip: The range is longest when \theta = 45^\circ.
  5. Path Equation (the curve it follows):
    • y = x \tan \theta - \frac{g x^2}{2 u^2 \cos^2 \theta}
  6. Speed at Any Time (t):
    • Horizontal: v_x = u \cos \theta (stays the same).
    • Vertical: v_y = u \sin \theta - gt
    • Total speed: v = \sqrt{v_x^2 + v_y^2}

For horizontal projection (from a height h, with horizontal speed u):

  • Time to hit the ground: T = \sqrt{\frac{2h}{g}}
  • Distance traveled: R = u \sqrt{\frac{2h}{g}}
  • Vertical speed on impact: v_y = \sqrt{2gh}

Projectile Motion Complete Video Lecture 100% free

Equation of Motion & Projectile Motion

Free TGT PGT Physics Practice Test On Projectile Motion

Think you’ve got projectile motion down? Prove it with our free practice test from Physics Scholar. It’s packed with MCQs and numericals to mimic real TGT PGT Physics exam questions.

1. 
Projectile Motion is an example of: प्रक्षेप्य गति किसका उदाहरण है?

2. 
A particle covers 50 m distance when projected with an initial speed. On the same surface it will cover a distance, when projected with double the initial speed:

एक कण जब प्रारम्भिक चाल से प्रक्षेपित किया जाता है, तो यह 50 m दूरी तय करता है। जब इसे प्रारम्भिक चाल से दो गुने चाल से फेंका जाये, तो तय की गयी दूरी होगी -

3. 
A projectile is projected with kinetic energy K . If it has the maximum possible horizontal range, then its kinetic energy at the highest point will be: एक प्रक्षेप्य को गतिज ऊर्जा K से प्रक्षेपित किया जाता है। यदि यह अधिकतम सम्भव क्षैतिज परास तय करता है, तो अधिकतम ऊँचाई पर इसकी ऊर्जा गतिज ऊर्जा होगी -

4. 
A stone is thrown at an angle $ \theta $ to the horizontal reaches a maximum height H . Then the time of flight of stone will be: क्षेतिज से $ \theta $ कोण पर प्रक्षेपित एक पत्थर अधिकतम H ऊँचाई तब पहुँचाता है। तो पत्थर का उड्डयन काल है -

5. 
A person can throw a stone to maximum height of h meter. The maximum distance to which he can throw the stone is : एक व्यक्ति एक पत्थर को अधिकतम h मीटर ऊँचाई तक फेंक सकता है। तो अधिकतम दूरी जहाँ तक वह पत्थर को फेक पायेगा -

6. 
Two balls of same mass are projected with the same speed one vertically upwards and the other at angle 60° with the vertical. The ratio of their potential energy at the highest point is :

समान द्रव्यमान के दो गोले समान चाल से, एक ऊर्ध्वाधर ऊपर की ओर तथा दूसरा ऊर्ध्वाधर से 60° कोण पर, प्रक्षेपित किया जाता है, तो उच्चतम बिन्दु पर स्थितिज ऊर्जाओं का अनुपात होगा -

7. 
Ratio of minimum kinetic energies of two projectiles of same mass is ( 4: 1 ). The ratio of the maximum height attained by them is also ( 4 : 1 ).The ratio of their ranges would be :

समान द्रव्यमान के दो प्रक्षेप्यों की न्यूनतम गतिज ऊर्जाओं का अनुपात ( 4: 1 ) है। उनके द्वारा प्राप्त अधिकतम ऊँचाइयों का अनुपात ( 4: 1 ) है। उनके परासों का अनुपात होगा -

8. 
A projectile is thrown at an angle of $ 40^{\circ}$ with the horizontal and its range is $ \mathrm{R}{1} $. Another projectile is thrown at an angle of $ 40^{\circ} $ with the vertical and its range is $ R_{2} $. What is the relation between $ R_{1} $ and $ \mathrm{R}{2} $ ?

क्षैतिज से $ 40^{\circ} $ कोण पर प्रक्षेपित प्रक्षेप्य का परास $ \mathrm{R}{1}$ है। दूसरे प्रक्षेपण में यह ऊर्ध्वाधर से $40^{\circ}$ पर फेंका जाता है, तो इसका परास $ R_{2} $ है। $ R_{1}$ तथा $ R_{2}$ में सम्बन्ध है -

  • (a) $( \mathrm{R}{1}=\mathrm{R}{2} )$
  • (b) $( \mathrm{R}{1}=2 \mathrm{R}{2} )$
  • (c) $( \mathrm{R}{2}=2 \mathrm{R}{1} )$
  • (d) $( \mathrm{R}{1}=\frac{4 R{2}}{5} )$

9. 
A projectile has a time of flight T and range R . If the time of flight is doubled, what happens to the range? एक प्रक्षेप्य का उड्डयन काल T तथा R परास है। यदि उड्डयन काल दो गुना कर दिया जाय तो इसका परास हो जायेगा -

10. 
The horizontal range of a projectile is maximum when the angle of projection is: प्रक्षेप्य का क्षैतिज परास अधिकतम होता है जब प्रक्षेपण कोण होता है:

11. 
At the highest point of a projectile's trajectory, which quantity becomes zero? प्रक्षेप्य के प्रक्षेप पथ के उच्चतम बिंदु पर कौन सी राशि शून्य हो जाती है?

12. 
The time of flight of a projectile depends on: प्रक्षेप्य के उड़ान के समय पर निर्भर करता है:

13. 
Two projectiles are fired at the same speed but at angles $30^\circ$ and $60^\circ$. Their horizontal ranges will be: दो प्रक्षेप्य एक ही गति से लेकिन $30^\circ$ और $60^\circ$ कोण पर फेंके जाते हैं। उनका क्षैतिज परास होगा:

14. 
The trajectory of a projectile is a: प्रक्षेप्य का प्रक्षेप पथ होता है:

15. 
If air resistance is considered, which quantity decreases compared to ideal projectile motion? यदि वायु प्रतिरोध माना जाए, तो आदर्श प्रक्षेप्य गति की तुलना में कौन सी राशि घट जाती है?

16. 
The angle between velocity and acceleration at the highest point of a projectile is: प्रक्षेप्य के उच्चतम बिंदु पर वेग और त्वरण के बीच का कोण है:

17. 
A projectile is fired horizontally from a height. Its time of flight depends on: एक प्रक्षेप्य को क्षैतिज रूप से एक ऊंचाई से फेंका जाता है। इसका उड़ान समय निर्भर करता है:

18. 
10. The ratio of maximum height to horizontal range when $\theta = 45^\circ$ is: अधिकतम ऊंचाई और क्षैतिज परास का अनुपात जब $\theta = 45^\circ$ होता है, वह है:

Learn More with Physics Scholar

Want to dive deeper? Physics Scholar has you covered:

  • Video Lessons: Watch our free tutorials on projectile motion, made for TGT PGT students.
  • Practice Quizzes: Try our quick quizzes to test your understanding.
  • Study Guides: Grab our downloadable notes for all Physics topics.

Tips to Ace Projectile Motion

  • Know Your Formulas: Jot them down a few times to lock them in.
  • Practice Problems: Solve at least 10 numericals a day—it builds confidence.
  • Sketch It Out: Draw the motion path to see what’s happening.
  • Watch for Exam Favorites: Questions on range, time of flight, and maximum height pop up a lot in TGT PGT 2025.

FAQs on Projectile Motion for TGT PGT Exams

Here are some common questions that show up in TGT PGT Physics exams, answered simply:

  1. When is the range of a projectile maximum?
    It’s maximum at a 45° angle because \sin 2\theta is biggest (1) when 2\theta = 90^\circ.
  2. Does the angle affect time of flight?
    Yes! The formula T = \frac{2u \sin \theta}{g} shows time depends on \sin \theta. Bigger angles (up to 90°) mean longer flight time.
  3. Why doesn’t horizontal speed change?
    Without air resistance, no force acts horizontally, so v_x = u \cos \theta stays constant.
  4. What’s the shape of the path?
    It’s a parabola, thanks to steady horizontal motion and gravity pulling downward.
  5. How does speed affect height?
    Maximum height depends on u^2 (see H = \frac{u^2 \sin^2 \theta}{2g}), so doubling speed quadruples height.

Why Projectile Motion Matters for TGT PGT

This topic is a big deal in TGT PGT Physics exams. It’s not just about understanding—it’s a chance to score easy marks if you know your stuff. With Physics Scholar’s notes and practice tests, you can turn projectile motion into your strength.

Final Words

Want to shine in TGT PGT Physics 2025? Start with Physics Scholar’s resources. Use these notes to revise projectile motion, take the free practice test, and check out our videos and quizzes for extra practice. Keep at it, and you’ll be ready to ace your exam!

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Amit Patel
Amit Patel

Hello!  I am Amit Patel From Uttar Pradesh. I have done my  Masters in Physics (2018) & B.Ed. (Education), Now I am working with Physics Scholar (By Anup Sir) as a Technical Team Member & content writer specially on Educational Carrier Counselling for Teaching Exams. I am a lover of Physics so i also explore to write articles on Science & Technology.

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